Directions: Each of these questions contains two statements: |
Assertion [A] and Reason [R]. Each of these questions also has four alternative choices, any one of which is the correct answer. You have to select one of the codes [a], [b], [c] and [d] given below. |
Assertion [A] In a rhombus of side 15 cm, one of the diagonals is 20 cm long. |
The length of the second diagonal is \[\frac{AB}{AD}=\frac{AC}{AE}\]cm. |
Reason [R] The sum of the squares of the sides of a rhombus is equal to the sum of the squares of its diagonals. |
A) A is true, R is true; R is a correct explanation for A.
B) A is true, R is true; R is not a correct explanation for A.
C) A is true; R is False.
D) A is false; R is true.
Correct Answer: D
Solution :
According to the question, |
Given, AB = BC =CD=DA=15cm |
AC = 20 cm [let] |
Let BO = OD = x cm |
\[\therefore\] In \[\Delta BOC\], \[{{x}^{2}}+{{10}^{2}}={{15}^{2}}\] |
[by Pythagoras theorem] |
\[{{x}^{2}}=125\] |
\[x=5\sqrt{5}\] |
\[BD=2x=10\sqrt{5}\,cm\] |
Hence, Statement I is false and Statement II is true. |
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