A) \[{{E}_{1}}=6{{E}_{2}}\]
B) \[{{E}_{1}}=2{{E}_{2}}\]
C) \[{{E}_{1}}=4{{E}_{2}}\]
D) \[{{E}_{1}}=1/2{{E}_{2}}\]
E) \[{{E}_{1}}={{E}_{2}}\]
Correct Answer: B
Solution :
\[E\propto \frac{1}{\lambda }\ ;\ {{E}_{1}}=\frac{1}{8000}\ ;\ {{E}_{2}}=\frac{1}{16000}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{16000}{8000}=2\ \ \Rightarrow \ {{E}_{1}}=2{{E}_{2}}\]
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