A) ? 41 kJ mol?1
B) ?1312 kJ mol?1
C) ?164 kJ mol?1
D) ? 82 kJ mol?1
Correct Answer: D
Solution :
\[\frac{{{E}_{4}}}{{{E}_{2}}}=\frac{{{2}^{2}}}{{{4}^{2}}}=\frac{4}{16}=\frac{1}{4}\];\[{{E}_{4}}=\frac{{{E}_{2}}}{4}=\frac{-328}{4}=-82\,\,kJ/mol.\]You need to login to perform this action.
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