A) 1 : 2
B) 1 : 16
C) 8 : 1
D) 16 : 1
Correct Answer: D
Solution :
\[{{r}_{n}}\propto {{n}^{2}}:{{A}_{n}}\propto {{n}^{4}}\] \[\frac{{{A}_{2}}}{{{A}_{1}}}=\frac{n_{2}^{4}}{n_{1}^{4}}=\frac{{{2}^{4}}}{{{1}^{4}}}=\frac{16}{1}=16\,:1\]You need to login to perform this action.
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