A) ?3.4 eV
B) ?6.8 eV
C) ?1.7 eV
D) ? 2.7 eV
Correct Answer: A
Solution :
Energy of an electron \[E=\frac{-{{E}_{0}}}{{{n}^{2}}}\] For energy level \[(n=2)\] \[E=-\frac{13.6}{{{(2)}^{2}}}=\frac{-13.6}{4}=-3.4eV\].You need to login to perform this action.
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