A) 11.2 L
B) 22.4 L
C) 1 L
D) 44.8 L
Correct Answer: A
Solution :
Molecular weight \[=2\times V.D\]\[=2\times 11.2=22.4\] \[\because \] 22.4gm of gas occupies 22.4L at S.T.P. \[\therefore \] 11.2gm of gas occupies \[\frac{22.4}{22.4}\times 11.2=11.2L\].You need to login to perform this action.
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