A) 1.520
B) 0.995
C) 19.00
D) 9.00
Correct Answer: D
Solution :
\[\frac{\text{wt}\text{. of metal hydroxide }}{\text{wt}\text{. of metal oxide}}=\frac{EM+EO{{H}^{-}}}{EM+E{{O}^{-}}}\] \[=\frac{1.520}{0.995}=\frac{x+17}{x+8}\] \[=1.520x+1.520\times 8\]\[=0.995x+0.995\times 17\] \[1.520x+12.160=0.995x+16.915\] or \[0.525x=4.755\] \[x=\frac{4.755}{0.525}=9\].You need to login to perform this action.
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