A) I and II
B) I and IV
C) I and III
D) II, III and IV
Correct Answer: D
Solution :
\[CH_{3}^{+}=6+3-1=8{{e}^{-}},\] \[{{H}_{3}}{{O}^{+}}=3+8-1=10{{e}^{-}},\] \[N{{H}_{3}}=7+3=10{{e}^{-}},\] \[CH_{3}^{-}=6+3+1=10{{e}^{-}}\]You need to login to perform this action.
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