Answer:
No. of photons \[(n)=1000\] Wavelength \[\text{(}\lambda )={{10}^{6}}{{A}^{0}}={{10}^{6}}\times {{10}^{10}}m\] \[E=\frac{nhc}{\lambda }=\frac{1000\times 6.625\times {{10}^{-34}}\times 3\times {{10}^{8}}}{{{10}^{6}}\times {{10}^{-10}}}=\] \[19.875\times {{10}^{-19}}J\]
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