Answer:
\[{{X}^{3}}\]is isoelectronic with argon. \[\Rightarrow \]The number of electrons in\[{{X}^{3}}=18\]. \[\Rightarrow \]The number of protons in\[{{X}^{3}}=\]The number of electrons in neutral atom of \[x=183=15\]. The ratio of electrons to neutrons = 1 : 1 \[\Rightarrow \] The no. of neutrons (n) in \[X=15\]. Mass number (A) of\[X=15+15=30\]
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