question_answer

Find the number of electrons, protons and neutrons present in: (a) Nitrate ion                    (b) Sulphate ion

Answer:

(a) Nitrate ion is\[NO_{3}^{-1}\] Total number of electrons \[=7+(3\times 8)+1=7+24+1=32\] Total number of protons \[=7+(3\times 8)=7+24=31\] Total number of neutrons \[=7+(3\times 8)=7+24=31\] (b) Sulphate ion is\[SO_{4}^{-2}\] Total number of electrons \[=16+(4\times 8)+2=16+32+2=50\] Total number of protons \[=16+(4\times 8)=16+32=48\] Total number of neutrons \[=16+(4\times 8)=16+32=48\]