question_answer

The electronic configuration of a di-positive metal ion \[{{M}^{2+}}\]is 2, 8, 14 and its mass number is 56. Find the number of neutrons in its nucleus.

Answer:

Electron configuration of\[{{M}^{2+}}\]is 2, 8, 14 Mass number \[(A)=56\] Number of neutrons \[(n)=?\] We know that\[n=AZ\] How to get Z? Z = No. of protons = No. of electrons in the neutral atom\[=24+2=26\] \[\therefore \] \[n=56-26=30.\] Therefore, the no. of neutrons present in \[{{M}^{+2}}\]is 30.