question_answer

The ion that is iso-electronic with CO is: (a) \[O_{2}^{-}\]                                               (b) \[N_{2}^{+}\] (c) \[C{{N}^{-}}\]                              (d) \[O_{2}^{+}\]

Answer:

The no. of electrons in\[CO=6+8=14\] Therefore, we need to select the species containing 14 electrons. Let us check the same \[O_{2}^{-}=2\times 8+1=17\] \[N_{2}^{+}\text{=}2\times 71=13\] \[C{{N}^{}}=6+7+1=14\] \[O_{2}^{+}=2\times 81=15\] Therefore, \[C{{N}^{-}}\] is isoelectronic with CO.