Answer:
Let us find the number of electrons in each set
Not isoelectronic a) Species No. of electrons \[NO+\] \[7+8-1=14\] \[C_{2}^{2-}\] \[6+6+2=14\] \[O_{2}^{-}\] \[8+8+1=17\]
Not isoelectronic b) Species No. of electrons \[{{N}_{2}}\] \[7+7=14\] \[C_{2}^{2-}\] \[6+6+2=14\] \[CO\] \[6+8=14\] \[NO\] \[7+8=15\]
Isoelectronic Therefore the set of species containing CO, \[N{{O}^{+}},C{{N}^{}},C_{2}^{2-}\]are isoelectronic with each other. c) Species No. of electrons \[CO\] \[6+8=14\] \[N{{O}^{+}}\] \[7+8-1=14\] \[C{{N}^{-}}\] \[6+8=14\] \[C_{2}^{2-}\] \[6+6+2=14\]
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