Answer:
The no. of electrons in\[CO=6+8=14\] Therefore, we need to select the species containing 14 electrons. Let us check the same \[O_{2}^{-}=2\times 8+1=17\] \[N_{2}^{+}\text{=}2\times 71=13\] \[C{{N}^{}}=6+7+1=14\] \[O_{2}^{+}=2\times 81=15\] Therefore, \[C{{N}^{-}}\] is isoelectronic with CO.
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