Answer:
Given: No. of electrons in A = No. of protons in A = No. of neutrons in \[A=x\] No. of electrons in B = No. of protons in B = No. of neutrons in\[B=y\] But\[y=2x\]. EC of A = 2, 8 (as it contains 8 electrons in L shell) \[\therefore \] The no. of electrons in A,\[x=10\] \[\Rightarrow \]No. of protons in A = No. of neutrons in\[A=x=10\]. Therefore A is Neon. We know that\[y=2x=20\]. \[\Rightarrow \]No. of proton in\[B=y=20\] Hence, B is calcium.
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