Answer:
\[x=a.m.u=1.66\times {{10}^{27}}kg\] \[y=1\text{ }kg\] \[\therefore \]\[\frac{y}{x}=\frac{1\,kg}{1.66\times {{10}^{-27}}kg}\cong 6.023\times {{10}^{26}}\]
You need to login to perform this action.
You will be redirected in
3 sec