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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    In a hydrogen atom, the distance between the electron and proton is \[2.5\times {{10}^{-11}}\,m\]. The electrical force of attraction between them will be                                                               [Pb. PMT 2000]

    A)            \[2.8\times {{10}^{-7}}\,N\]  

    B)            \[3.7\times {{10}^{-7}}N\]

    C)            \[6.2\times {{10}^{-7}}N\]     

    D)            \[9.1\times {{10}^{-7}}N\]

    Correct Answer: B

    Solution :

               \[F=\frac{9\times {{10}^{9}}\times 1.6\times {{10}^{-19}}\times 1.6\times {{10}^{-19}}}{{{(2.5\times {{10}^{-11}})}^{2}}}=3.7\times {{10}^{-7}}N\]


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