A) \[1.05\times {{10}^{-34}}\]
B) \[2.1\times {{10}^{-34}}\]
C) \[3.15\times {{10}^{-34}}\]
D) \[-2.1\times {{10}^{-34}}\]
Correct Answer: C
Solution :
Energy of electron in H atom \[{{E}_{n}}=\frac{-13.6}{{{n}^{2}}}eV\] \[\Rightarrow -1.5=\frac{-13.6}{{{n}^{2}}}\Rightarrow {{n}^{2}}=\frac{13.6}{1.5}=3\] Now angular momentum \[p=n\frac{h}{2\pi }=\frac{3\times 6.6\times {{10}^{-34}}}{2\times 3.14}=3.15\times {{10}^{-34}}J\times \sec \]
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