JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    The time of revolution of an electron around a nucleus of charge Ze in nth Bohr orbit is directly proportional to [MP PET 2003]

    A)            n    

    B)            \[\frac{{{n}^{3}}}{{{Z}^{2}}}\]

    C)            \[\frac{{{n}^{2}}}{Z}\]      

    D)            \[\frac{Z}{n}\]

    Correct Answer: B

    Solution :

                       \[T=\frac{2\pi r}{v}\]; r = radius of nth orbit\[=\frac{{{n}^{2}}{{h}^{2}}}{\pi mZ{{e}^{2}}}\]                    v = speed of \[{{e}^{-}}\] in nth orbit \[=\frac{z{{e}^{2}}}{2{{\varepsilon }_{0}}nh}\]            \ \[T=\frac{4\varepsilon _{0}^{2}{{n}^{3}}{{h}^{3}}}{m{{Z}^{2}}{{e}^{4}}}\] Þ \[T\propto \frac{{{n}^{3}}}{{{Z}^{2}}}\]          


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