A) \[{{r}_{0}}\]
B) \[4{{r}_{0}}\]
C) \[{{r}_{0}}/16\]
D) \[16{{r}_{0}}\]
Correct Answer: D
Solution :
\[{{r}_{n}}\propto {{n}^{2}}\Rightarrow \frac{{{r}_{4}}}{{{r}_{1}}}={{\left( \frac{4}{1} \right)}^{2}}=\frac{16}{1}\Rightarrow {{r}_{4}}=16\ {{r}_{1}}\Rightarrow {{r}_{4}}=16\ {{r}_{0}}\]
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