A) \[\frac{R}{4}\]
B) \[\frac{3R}{4}\]
C) \[\frac{R}{2}\]
D) 2R
Correct Answer: B
Solution :
For Lyman series \[\bar{\nu }=\frac{1}{\lambda }=R\,\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{n}^{2}}} \right)\]here n=2, 3, 4, 5..... For first line \[\bar{\nu }=R\,\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)\Rightarrow \bar{\nu }=R\,\left( 1-\frac{1}{4} \right)=\frac{3R}{4}\]
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