A) \[\frac{25}{9}\]
B) \[\frac{17}{6}\]
C) \[\frac{9}{5}\]
D) \[\frac{4}{3}\]
Correct Answer: D
Solution :
For Lyman series \[\frac{1}{{{\lambda }_{\max }}}=R\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right]=\frac{3}{4}R\] and \[\frac{1}{{{\lambda }_{\min }}}=R\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{\infty }^{2}}} \right]=\frac{R}{1}\Rightarrow \frac{{{\lambda }_{\max }}}{{{\lambda }_{\min }}}=\frac{4}{3}\]
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