A) 5 : 9
B) 5 : 36
C) 1 : 4
D) 3 : 4
Correct Answer: A
Solution :
\[\frac{1}{\lambda }=R\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\Rightarrow \frac{{{\lambda }_{\min }}}{{{\lambda }_{\max }}}=\frac{\left[ \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right]}{\left[ \frac{1}{{{2}^{2}}}-\frac{1}{\infty } \right]}=\frac{5}{9}\]
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