A) \[2\pi hc/{{e}^{2}}\]
B) \[{{e}^{2}}h/2\pi c\]
C) \[{{e}^{2}}c/2\pi h\]
D) \[2\pi {{e}^{2}}/hc\]
Correct Answer: D
Solution :
Speed of electron in nth orbit (in CGS) \[{{v}_{n}}=\frac{2\pi Z{{e}^{2}}}{nh}\](k = 1) For first orbit \[{{H}_{2}}\]; n = 1 and Z = 1 So \[v=\frac{2\pi {{e}^{2}}}{h}\] Þ \[\frac{v}{c}=\frac{2\pi {{e}^{2}}}{hc}\]
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