A) \[13.6\ eV\]
B) \[+\frac{13.6}{9}eV\]
C) \[-\frac{13.6}{3}eV\]
D) \[-\frac{3}{13.6}eV\]
Correct Answer: B
Solution :
Energy required to knock out the electron in the nth orbit\[=+\frac{13.6}{{{n}^{2}}}eV\] Þ \[{{E}_{3}}=+\frac{13.6}{9}eV\].
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