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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    Radius of the first orbit of the electron in a hydrogen atom is 0.53 Å. So, the radius of the third orbit will be [Kerala (Engg.) 2001]

    A)            2.12 Å                                      

    B)            4.77 Å

    C)            1.06 Å                                      

    D)            1.59 Å

    Correct Answer: B

    Solution :

               \[{{r}_{n}}\propto {{n}^{2}}\Rightarrow \frac{{{r}_{3}}}{{{r}_{1}}}=\frac{{{3}^{2}}}{1}\Rightarrow {{r}_{3}}=9{{r}_{1}}=9\times 0.53=4.77{\AA}\]


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