A) 13.6 eV
B) 3.4 eV
C) 12.09 eV
D) 1.51 eV
Correct Answer: C
Solution :
For \[n=1,\ {{E}_{1}}=-\frac{13.6}{{{(1)}^{2}}}=-13.6\ eV\] and for n = 3, \[{{E}_{3}}=-\frac{13.6}{{{(3)}^{2}}}=-1.51\ eV\] So required energy \[={{E}_{3}}-{{E}_{1}}=-1.51-(-13.6)=12.09\ eV\]You need to login to perform this action.
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