JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    The first line in the Lyman series has wavelength l. The wavelength of the first line in Balmer series is [MH CET (Med.) 2001]

    A)            \[\frac{2}{9}\,\lambda \]

    B)            \[\frac{9}{2}\,\lambda \]

    C)            \[\frac{5}{27}\,\lambda \]      

    D)            \[\frac{27}{5}\lambda \]

    Correct Answer: D

    Solution :

                       For first line in Lyman series \[{{\lambda }_{{{L}_{1}}}}=\frac{4}{3\ R}\]                ..... (i)                    For first line in Balmer series \[{{\lambda }_{{{B}_{1}}}}=\frac{36}{5\ R}\]            ..... (ii)                    From equation (i) and (ii)            \[\frac{{{\lambda }_{{{B}_{1}}}}}{{{\lambda }_{{{L}_{1}}}}}=\frac{27}{5}\Rightarrow {{\lambda }_{{{B}_{1}}}}=\frac{27}{5}{{\lambda }_{{{L}_{1}}}}\Rightarrow {{\lambda }_{{{B}_{1}}}}=\frac{27}{5}\lambda \]


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