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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    Four lowest energy levels of H-atom are shown in the figure. The number of possible emission lines would be                                                                                                                                                                                                                         [MP PMT 2001]                      

    A)            3    

    B)            4

    C)            5    

    D)            6

    Correct Answer: D

    Solution :

                       Number of possible emission lines \[=\frac{n(n-1)}{2}\]                    Where n = 4; Number \[=\frac{4(4-1)}{2}=6.\]


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