A) 1 : 2 : 3
B) 1 : 4 : 9
C) 4 : 9 : 36
D) 3 : 2 : 1
Correct Answer: C
Solution :
\[\frac{1}{\lambda }=R{{Z}^{2}}\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\Rightarrow \lambda \propto \frac{1}{{{Z}^{2}}}\] \[{{\lambda }_{L{{i}^{++}}}}:{{\lambda }_{H{{e}^{+}}}}:{{\lambda }_{H}}=4:9:36\]
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