A) 13.6 eV
B) 54.4 eV
C) 27.2 eV
D) 6.8 eV
Correct Answer: B
Solution :
\[{{E}_{n}}=-\frac{13.6{{z}^{2}}}{{{n}^{2}}}eV\Rightarrow {{E}_{1}}=-\frac{13.6\times {{(2)}^{2}}}{{{(1)}^{2}}}=-54.4\ eV\]You need to login to perform this action.
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