A) 910 Å, 1213 Å
B) 5463 Å, 7858 Å
C) 1315 Å, 1530 Å
D) None of these
Correct Answer: A
Solution :
\[\frac{1}{{{\lambda }_{\max }}}=R\,\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} \right]\] Þ \[{{\lambda }_{\max }}=\frac{4}{3R}\approx 1213\,{\AA}\] and \[\frac{1}{{{\lambda }_{\min }}}=R\,\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{\infty } \right]\] Þ \[{{\lambda }_{\min }}=\frac{1}{R}\approx 910\,{\AA}\]You need to login to perform this action.
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