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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    Energy of the electron in nth orbit of hydrogen atom is given by \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV\]. The amount of energy needed to transfer electron from first orbit to third orbit is [MH CET 2002; Kerala PMT 2002]

    A)            13.6 eV                                   

    B)            3.4 eV

    C)            12.09 eV                                 

    D)            1.51 eV

    Correct Answer: C

    Solution :

                       For \[n=1,\ {{E}_{1}}=-\frac{13.6}{{{(1)}^{2}}}=-13.6\ eV\]                    and for n = 3, \[{{E}_{3}}=-\frac{13.6}{{{(3)}^{2}}}=-1.51\ eV\]                    So required energy            \[={{E}_{3}}-{{E}_{1}}=-1.51-(-13.6)=12.09\ eV\]


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