A) ? 5.40 eV
B) ? 2.72 eV
C) ? 0.85 eV
D) ? 0.54 eV
Correct Answer: D
Solution :
\[A={{A}_{0}}{{\left( \frac{1}{2} \right)}^{\frac{t}{{{T}_{1/2}}}}}\Rightarrow \frac{1}{64}={{\left( \frac{1}{2} \right)}^{\frac{60}{{{T}_{1/2}}}}}\]Þ \[{{E}_{5}}=\frac{-13.6}{{{5}^{2}}}=\frac{-13.6}{25}=-0.54\ eV\]You need to login to perform this action.
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