A) ? 13.6 eV
B) ? 27.2 eV
C) ? 6.8 eV
D) None of these
Correct Answer: D
Solution :
\[{{E}_{{{n}_{1}}\to {{n}_{2}}}}=-13.6\left[ \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right];{{n}_{1}}=2\And {{n}_{2}}=1\] \[\Rightarrow {{E}_{II}}\to {{E}_{I}}=-13.6\times \frac{3}{4}=-10.2\ eV\]
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