A) \[n{{a}_{0}}\]
B) \[{{a}_{0}}\]
C) \[{{n}^{2}}{{a}_{0}}\]
D) \[\frac{{{a}_{0}}}{{{n}^{2}}}\]
Correct Answer: C
Solution :
\[r\propto {{n}^{2}}\] Þ \[{{r}_{n}}={{n}^{2}}{{a}_{0}}\] \[(\because {{r}_{1}}={{a}_{0}})\]
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