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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    Minimum energy required to takeout the only one electron from ground state of \[H{{e}^{+}}\] is                           [CPMT 2002]

    A)            13.6 eV                                   

    B)            54.4 eV

    C)            27.2 eV                                   

    D)            6.8 eV

    Correct Answer: B

    Solution :

               \[{{E}_{n}}=-\frac{13.6{{z}^{2}}}{{{n}^{2}}}eV\Rightarrow {{E}_{1}}=-\frac{13.6\times {{(2)}^{2}}}{{{(1)}^{2}}}=-54.4\ eV\]


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