A) \[2{{\nu }_{0}}\]
B) \[4{{\nu }_{0}}\]
C) \[{{\nu }_{0}}/2\]
D) \[{{\nu }_{0}}/4\]
Correct Answer: B
Solution :
\[\nu \propto {{Z}^{2}}\Rightarrow \frac{{{\nu }_{{{H}_{2}}}}}{{{\nu }_{He}}}={{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{4}\Rightarrow {{\nu }_{He}}=4{{\nu }_{{{H}_{2}}}}\]= 4n0
You need to login to perform this action.
You will be redirected in
3 sec
