A) 13.6 eV
B) 27.2 eV
C) 54.4 eV
D) 100 eV
Correct Answer: C
Solution :
For the ionization of second He electron. \[H{{e}^{+}}\] will act as hydrogen like atom. Hence ionization potential \[={{Z}^{2}}\times 13.6\,volt={{(2)}^{2}}\times 13.6=54.4\,V\]
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