A) \[\frac{3}{16}\times {{10}^{5}}\]
B) \[\frac{3}{16}\times {{10}^{15}}\]
C) \[\frac{9}{16}\times {{10}^{15}}\]
D) \[\frac{3}{4}\times {{10}^{15}}\]
Correct Answer: C
Solution :
\[\frac{1}{\lambda }=R\,\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{4}^{2}}} \right)=\frac{3R}{16}\Rightarrow \lambda =\frac{16}{3R}=\frac{16}{3}\times {{10}^{-5}}cm\] Frequency \[n=\frac{c}{\lambda }=\frac{3\times {{10}^{10}}}{\frac{16}{3}\times {{10}^{-5}}}=\frac{9}{16}\times {{10}^{15}}Hz\]You need to login to perform this action.
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