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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    The shortest wavelength in the Lyman series of hydrogen spectrum is 912 Å corresponding to a photon energy of 13.6 eV. The shortest wavelength in the Balmer series is about                   [MP PMT 2004]

    A)            3648 Å                                     

    B)            8208 Å

    C)            1228 Å                                     

    D)            6566 Å

    Correct Answer: A

    Solution :

                       In Lyman series \[{{({{\lambda }_{\min }})}_{L}}=\frac{1}{R}\] and \[{{({{\lambda }_{\min }})}_{B}}=\frac{4}{R}\]            Þ \[{{({{\lambda }_{\min }})}_{B}}=4\times {{({{\lambda }_{\min }})}_{L}}=4\times 912=3648\,{\AA}\]


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