A) \[4{{E}_{n}}\]
B) \[{{E}_{n}}/4\]
C) \[2{{E}_{n}}\]
D) \[{{E}_{n}}/2\]
Correct Answer: A
Solution :
\[{{E}_{n}}\propto {{Z}^{2}}\] Þ \[\frac{{{({{E}_{n}})}_{He}}}{{{({{E}_{n}})}_{H}}}=\frac{Z_{He}^{2}}{Z_{H}^{2}}=4\] Þ \[{{({{E}_{n}})}_{He}}=4\times {{({{E}_{n}})}_{H}}\]
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