A) \[\beta \]
B) n
C) \[{{n}^{-2}}\]
D) \[{{n}^{2}}\]
Correct Answer: D
Solution :
Bohr radius \[r=\frac{{{\varepsilon }_{0}}{{n}^{2}}{{h}^{2}}}{\pi Zm{{e}^{2}}};\ \ \therefore r\propto {{n}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
