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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength \[\lambda \] is emitted. The wavelength of photon produced during its transition from \[\frac{4E}{3}\] level to E is [CPMT 1989]       

    A)            \[\lambda /3\]                    

    B)            \[3\lambda /4\]

    C)            \[4\lambda /3\]                  

    D)            \[3\lambda \]

    Correct Answer: D

    Solution :

                       \[2E-E=\frac{hc}{\lambda }\Rightarrow E=\frac{hc}{\lambda }\]            \[\frac{4E}{3}-E=\frac{hc}{\lambda '}\Rightarrow \frac{E}{3}=\frac{hc}{\lambda '}\ \ \therefore \frac{\lambda '}{\lambda }=3\Rightarrow \lambda '=3\lambda \]


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