A) \[{{Z}^{2}}{{n}^{2}}\]
B) \[\frac{{{Z}^{2}}}{{{n}^{2}}}\]
C) \[\frac{{{Z}^{2}}}{n}\]
D) \[\frac{{{n}^{2}}}{Z}\]
Correct Answer: D
Solution :
\[r=\frac{{{\varepsilon }_{0}}{{n}^{2}}{{h}^{2}}}{\pi Zm{{e}^{2}}};\ \ \therefore r\propto \frac{{{n}^{2}}}{Z}\]
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