question_answer

In the nth orbit, the energy of an electron \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV\]for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be [MP PMT 1987; CPMT 1991, 97; RPMT 1999; DCE 2001; Kerala PMT 2004]

A)            \[10.2\ eV\]                          

B)            \[12.1\ eV\]

C)            \[13.6\ eV\]                          

D)            \[3.4\ eV\]

Correct Answer: A

Solution :

                                      \[{{E}_{1\to 2}}=-3.4-(13.6)=+10.2\,eV\]