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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    A hydrogen atom (ionisation potential 13.6 eV) makes a transition from third excited state to first excited state. The energy of the photon emitted in the process is                [MNR 1995]

    A)            1.89 eV                                   

    B)            2.55 eV

    C)            12.09 eV                                 

    D)            12.75 Ev

    Correct Answer: B

    Solution :

               Energy released\[=13.6\left[ \frac{1}{{{(2)}^{2}}}-\frac{1}{{{(4)}^{2}}} \right]=2.55\,eV\]


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