A) \[\frac{16}{3R}\]
B) \[\frac{2R}{16}\]
C) \[\frac{3R}{16}\]
D) \[\frac{4R}{16}\]
Correct Answer: C
Solution :
Wave number \[\frac{1}{\lambda }=R\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]=R\left[ \frac{1}{4}-\frac{1}{16} \right]=\frac{3R}{16}\]
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