A) 1/2
B) 2
C) \[-1/2\]
D) ? 2
Correct Answer: C
Solution :
\[K.E=\frac{kZ{{e}^{2}}}{2r}\] and \[P.E.=-\frac{kZ{{e}^{2}}}{r};\] \ \[\frac{K.E.}{P.E.}=-\frac{1}{2}\].You need to login to perform this action.
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